2 replies to this topic

[mutago]

I have this code that post ajax form to database1.php and i now want it to post also to another page database2.php

how can i achieve that

 

 
 
function sendData(url, data) {
 
$.ajax({
url: 'database1.php',
 
type: 'POST',
processData: false,
contentType: false,
data: data,
cache: false
}).done(function (data) {
 
});
}

 

Thanks

[dargueta]

Change url to be 'database2.php' instead of 'database1.php'.

[lespauled]

Change the hard coded url to the variable url  and call that function with any url you wish

Edited by lespauled, 09 September 2015 - 05:38 AM.