I am Prateek Tyagi,PHP beginner,I want to get save a image in mysql database but there are some warnings on execution..
Warning: fopen(C:\xampp\tmp\php99D.tmp) [function.fopen]: failed to open stream: No such file or directory in C:\xampp\htdocs\php_db\user.php on line 25
Warning: filesize() [function.filesize]: stat failed for C:\xampp\tmp\php99D.tmp in C:\xampp\htdocs\php_db\user.php on line 26
Warning: fread() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\php_db\user.php on line 26
Warning: fclose() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\php_db\user.php on line 28
I tried a lot but could'nt find the result.Please help me !
Thankyou.
HERE IS THE CODE.
<?php
if(!is_dir("images"))
{
mkdir("images");
}
if($_FILES['image']['error']==0)
{
if($_FILES['image']['type']=="image/jpeg" ||$_FILES['image']['type']=="image/gif")
{
$source=$_FILES['image']['tmp_name'];
$target="images/".$_FILES['image']['name'];
move_uploaded_file($source, $target);
}
}
else {
echo "Error:".$_FILES['image']['error'];
}
$imgname=$_FILES['image']['name'];
$tmpname=$_FILES['image']['tmp_name'];
$fp=fopen("$tmpname",'r');
$data=fread($fp,filesize($tmpname));
$data=addslashes($data);
fclose($fp);
$con=mysql_connect("localhost","PratikTyagi","");
if(!$con)
{
die("Could not connect to database.<br>".mysql_error());
}
mysql_select_db("php_db",$con);
$imgquery="insert into photo values('$data','$imgname',$size)";
mysql_query($imgquery,$con);
?>
Edited by BenW, 04 October 2012 - 02:38 PM.
Added code tags for readability
