F: (0)
E:** (2)
D:****** (6)
C:*********(9)
B:**** (4)
A:**(2)
how can solved this problem?
many thanks to you guys
program barchart;
var
count : array ['A'..'F'] of integer;
mark : array [1..15] of integer;
i: integer;
ch: char;
procedure countgrade;
var
ch : char;
i : integer;
begin
for ch := 'A' to 'F' do
count[ch] := 0;
for i := 1 to 15 do
case mark[i] of
0..50 : count['F'] := count['F'] + 1;
51..60 : count['E'] := count['E'] + 1;
61..70 : count['D'] := count['D'] + 1;
71..80 : count['C'] := count['C'] + 1;
81..90 : count['B'] := count['B'] + 1;
91..100 : count['A'] := count['A'] + 1;
end
end;
procedure plotchart;
var
ch : char;
i : integer;
begin
for ch := 'F' to 'A' do
begin
write(ch, ':');
for i := 1 to count[ch] do
write('*');
writeln('(', count[ch], ')')
end
end;
begin
for i:=1 to 15 do
begin
write('Enter test mark for student ',i,': ' );
readln(mark[i]);
end;
countgrade;
plotchart;
readln
end.


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