1 reply to this topic

[restin84]

Simple leap year calculator just wondering if the logic is good. All the numbers I've tested so far have worked out


def LeapYear(year):
if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
return True

[Flying Dutchman]

Seems good. You can test it with calendar module, it has a isleap method.

import calendar
print calendar.isleap(1900)