3 replies to this topic

[1Maddoc]

Hi I just started using VB 2008 and I am working with random number.
I got the code below from this site.

Dim random as New Random
dim num as integer
num=random.next(1,21)

My question is...How can I get out the duplicates numbers and replace them with the correct number?

Please help .

[WingedPanther]

You'll have to clarify. One of the properties of random numbers is that, given a long enough sequence, you should expect to get duplicates. Given that, what are you trying to do? What is a "correct number"?

[Blimp]

I think he means not having duplicates.. You must understand that as you go down the line, it will become increasingly difficult for the program to find a number that isn't used. You could probably use a For Each statement, but without any actual knowledge of how far into your code you are, we have no way of helping you.

[WingedPanther]

I figured as much. Usually, I'll do something like use an array or list to store the numbers I want to scramble, and reduce the range of random numbers by one while removing the selected item from the list.