4 replies to this topic

[atoivan]

how do i make this nested if decision work

is the weather good,
if yes
I will go out in the yard.
if No
"Oh sorry u can not go out sit indoors \n"

int main()

{

puts("this is just to test nested ifs \n");


char num0;


printf("press y for Yes and n for No \n");

printf("is the weather good \n");

scanf("%c",&num0);

if (num0 == 'y')

{

printf("Good u can go out now \n");

if(num0 == 'n')

printf("Oh sorry u can not go out sit indoors \n");

}

return 0;

}

[ZekeDragon]

This program does not require a nested if statement. You nearly have it right, all you'd have to do is get rid of the internal if statement and do as follows:

if (num0 == 'y')

{

    puts("Good u can go out now.");

}

else

{

    puts("Oh sorry u can not go out sit indoors.");

}

I'd also check if the user input is correct.

[atoivan]

thank z

[atoivan]

what is u want to do it nested if how will it be

[Alexander]

atoivan said:

what is u want to do it nested if how will it be

I am sure you could do it like this, to provide a more useful nesting.

if (num0 == 'y' || num0 == 'n') {

    if(num0 == 'y') {

         ...

    } else {

         ...

    }

} else {

   /* invalid input */

}