7 replies to this topic

[arunjib]

Please suggest a formula to sum up the following series
(1+2)/(1*2) + (1+2+3)/(1*2*3) + ........ + (1+2+3+ .... + n)/(1*2*3* .... * n)

i have written the code as follows but there is error in my formula

public class Series

{

public static void main(int n)

{

int i;

double s=0;

for(i=1;i<=n;i++)

s=s+(double)(i+(i+1))/(i*(i+1));

System.out.println("Sum = "+s);

    }

}

[Sayan Choudhury]

Please help me about the above problem. I need it too.

[lethalwire]

I'd create 2 methods. One that computes a summation to n and another that computes the factorial to n.

Then I'd use these in my for loop

For( I to N )
Num += sum(I) / factorial(I);

[wim DC]

double sum = 1.0;

        double product = 1.0;

        double total = 0.0;


        for (int i = 2; i <= 3; i++) {

            sum += i;

            product *= i;

            total += sum / product;

        }

        System.out.println(total);

[Sayan Choudhury]

Thank you very much doing the problem

here is my complete code

public class Series

{

public static void main(int n)

{

double sum = 1.0;

        double product = 1.0;

        double total = 0.0;


        for (int i = 2; i <= n; i++) {

            sum += i;

            product *= i;

            total += sum / product;

        }

        System.out.println(total);

    }

}

[lethalwire]

deja vu code.

[arunjib]

what does it mean? "deja vu code"

lethalwire said:

deja vu code.

[Sayan]

Thank u sir

---------- Post added at 06:17 PM ---------- Previous post was at 06:17 PM ----------

deja vu code ????????????:confused: