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In windows, when a file is opened with the default program, is argument0 the filepath

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Started by liamzebedee, May 17 2011 03:04 AM

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#1
liamzebedee
Posted 17 May 2011 - 03:04 AM

liamzebedee

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In windows, when a file is opened with the default program, is argument0(args[0]) the filepath.

#2
gregwarner
Posted 17 May 2011 - 08:51 AM

gregwarner

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In C++, argv[0] contains the path to the executable for the currently running program. However, in Java, args[0] contains the first user-specified argument.
Hofstadter's Law: It always takes longer than you expect, even when you take into account Hofstadter's Law.

– Douglas Hofstadter, Gödel, Escher, Bach: An Eternal Golden Braid

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