5 replies to this topic

[skypower]

I have

String in // taken from a single readline() input

then I have a check

 if (Character.isDigit(in.charAt(i)))

which is, let's say, true and then

for (int j = 1; j <=  (in.charAt(i)); j++) {
             System.out.println(""int "+ (int) in.charAt(i)+ "-"+in.charAt(i)); // for testing purposes 
        }

the i is standard in this example, say 5 and the charAt(i) is obviously a number since we passed the check, say 3

the program is supposed to get in the j loop 3 times, but instead it goes around 49-53 times (I changed the program and input and got various results)

What's wrong? :crying:

[wim DC]

Characters are very closely related to integers.
Check Ascii Table - ASCII character codes and html, octal, hex and decimal chart conversion
There are 2 important columns there 'DEC' and 'CHAR'
When you have char '3' in there, look in 'DEC' and there is the amount of times it will loop (51 for '3')

That is because you can't simply use a char as if it was an integer. You have to parse it by doing:

int number = Integer.parseInt(c + "");

Where c is a char variable. I do + "" to turn the char in a String.

[skypower]

Thank you Wim, I didn't know that. So in the code you showed you basicaly convert a char in a string in the parentheses and then convert that string in an int?

By the way, I found another solution before I saw your response.

in.charAt(i) -'0'

in the j loop

[wim DC]

Or you can do "-48" aswell ;)

[skypower]

wim DC said:

Or you can do "-48" aswell ;)

I guess you mean - "48" but the compiler won't let me do that, besides I am already confused with - '0' and this trick :P I will have to spend some time to learn those thingies.

[wim DC]

No, I really mean -48, as you see in the ascii table '0' is equal to 48.