4 replies to this topic

[arunjib]

Please help me in following code. The program always returns else part

public class reverseNumber

{

public void func(int n)

{

int d,r; r=0;

do

{

d=n%10;   // returns remainder

r=r*10+d;

n=n/10;   // returns quotient

}while(n!=0);

if(n==r)

System.out.println("palindrome");

else

System.out.println("not palindrome");

}

}

[ZekeDragon]

}while(n!=0);

if(n==r)

n must always equal 0 at the end of that do loop. Your do while loop adds value to r, so inevitably if n started > 9 then r must be > 0, therefore n will never == r. Thus, you get "not palindrome". Why are you using this method to determine a palindrome anyway, why not just take user input String object, make a reversed string, then use .equals()?

[arunjib]

Thank you ZekeDragon. I have already solved the problem with the help of the program given in the following link .

Java Palindrome Number,Java Palindrome Code,Example of Palindrome Number,Program of Java Palindrome Number

[ZekeDragon]

I'm asking why didn't you just do this:

public boolean isPalindrome(String check)

{

    return new StringBuilder(check).reverse().toString().equals(check);

}

instead of the complicated mathematical method?

[arunjib]

thanks to all