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DS=10FE; SS=1234; CS=74E3; ES=44FF; BP=6611; SI=00F1; DI=31FF; adressing byte and offset is 31AB . OpCode is 83h. The answer is 16681. I need to know step by step solution with detail explainations. I'm on the first course of software enginering, and I must to learn it.
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Posted 14 December 2010 - 10:45 AM
dargueta
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Writes binary right handed and hex left handed
- Programming Language:C, Java, C++, PHP, Python, Perl, Assembly, Bash, Others
- Learning:JavaScript
Ok, a few things:
1) We help with homework, but we don't do it for you. Walk me through your thought process.
2) I have no idea what your question is.
I would start by looking at Intel's instruction set manuals, volumes A and B. Volume B has an opcode map at the end that you'll find useful.
By the way, is the order of bytes in memory is 83 AB 31 or 83 31 AB?
1) We help with homework, but we don't do it for you. Walk me through your thought process.
2) I have no idea what your question is.
I would start by looking at Intel's instruction set manuals, volumes A and B. Volume B has an opcode map at the end that you'll find useful.
By the way, is the order of bytes in memory is 83 AB 31 or 83 31 AB?
sudo rm -rf /
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