6 replies to this topic

[snorifu]

Hello,
I just made this program but it doesn't work the way I want.

[B]#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

    int a;

    cout << "How many names?:";

    cin >> a;

    char name [a][10];

    int ra[a];

    for (int i=0;i<a;i++){

        cout << "name"<<i<<"?:";

        cin.getline (name [i],10);

        }

    for (int i=0;i<a;i++){

            ra[i]=rand() %100+1;

        }

    for (int i=0;i<a;i++){

    cout << name[i] << ":" << ra[i] << "\n"

        }

    cin >> ra[1];

}

[/B]

The problem is that if I execute the code I can't enter name0 it seems to jump directly to name 1.
Can anybody help with this?

[lintwurm]

This program works as expected.
Not sure what is wrong with yours though, sorry...

#include <iostream>
#include <stdlib.h>
using namespace std;
int main()
{
	int a;
	cout << "How many names?:";
	cin >> a;
	char name [a][10];
	int ra[a];
	for (int i=0;i<a;i++){
		cout << "name"<<i<<":";
		cin>>name[i];
	}
	for (int i=0;i<a;i++){
		ra[i]=rand() %100+1;
	}
	for (int i=0;i<a;i++)
	{
		cout << name[i] << ":" << ra[i] << "\n";
	}
	cin >> ra[1];
}

[WingedPanther]

The carriage return on your i=0 may be causing it to read in name[0] as an empty string.

[cocoa10]

This is just a though, because it worked for me, copy your posted code and try running it.

[snorifu]

WingedPanther said:

The carriage return on your i=0 may be causing it to read in name[0] as an empty string.

Is a carriage return the same as newline?
I don't see a newline sorry.
This is the output:

[brownhead]

I think wingedpanther is right. When your program takes in that 3, there's still a newline in the buffer (cause you hit enter after you put that 3 in didn't you?). You can call cin.get() if you'd like, which would take in a single character from the buffer. Or you could call cin.seekg(0, ios_base::end) which would place the get pointer at the end of the buffer, skipping whatever else is in the buffer.

[snorifu]

Ok thanks cin.get() did the trick:)