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# division problem?

variable type

3 replies to this topic

Speaks fluent binary

• Expert Member
• 1085 posts

Posted 10 October 2010 - 07:13 AM

I am trying to use java to divide a variable number inside a for loop by 3. For some reason it always has only one number after the decimal and it is always a 0. for what I am trying to do I need to know if 3 goes into it evenly so the numbers after the decimal are important for the algorithm I have made. I have tried using the variable types (double) & (float)

Note: Please do not suggest another way of finding if three goes evenly into something because 1) I may need to work with decimals in the future in which case this question is important for me to have answered. 2) this is for project euler and i would like to work out how to do things on my own; I'm only asking this because I'm confused with an aspect of the language not how to solve the problem. If my way is wrong I will discover it on my own and work out how to do it myself.

Thanks
~Zero
• 0

### #2 wim DC

wim DC

Roar

• Expert Member
• 2681 posts
• Programming Language:Java, JavaScript, PL/SQL
• Learning:Python

Posted 10 October 2010 - 07:52 AM

I'm only getting a zero as only decimal if i do int / int. (Ideone.com | 3TDo2)
```     double dNumber = 5.0;
double dThree = 3.0;
int iThree = 3;
int iNumber = 5;

double result = dNumber / iThree ;
System.out.println("double/int: " + result);

result = iNumber / dThree ;
System.out.println("int/double: " + result);

result = dNumber/ dThree;
System.out.println("double/double: " + result);

result = iNumber/ iThree;
System.out.println("int/int: " + result);
```

output:
```double/int: 1.6666666666666667
int/double: 1.6666666666666667
double/double: 1.6666666666666667
int/int: 1.0```

• 1

### #3 Alexander

Alexander

YOL9

• Moderator
• 3963 posts
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• Programming Language:C, C++, PHP, Assembly

Posted 10 October 2010 - 07:57 AM

Your description of the problem is too vague for us to guess what is going wrong without a sample code. An explicit integer cast after integer devision will do this (such as what oxano mentioned), which leads us to believe you hadn't casted it properly somewhere.
• 0

All new problems require investigation, and so if errors are problems, try to learn as much as you can and report back.

Speaks fluent binary

• Expert Member
• 1085 posts

Posted 10 October 2010 - 08:31 AM

that fixed it. I had set a double type variable to hold i/3 but i had set i as an int rather than a double. (>.<) My first time using a strongly typed language and doing math programmicly I usually just do data retrieval and writing. Sorry to waste your time and i should have posted the code, I forgot as i'm trying to get ready for work. thanks for the help. +rep

wont let me rep Null. Guess i can only give it one of you.
• 0

### Also tagged with one or more of these keywords: variable type

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