9 replies to this topic

[krishna sowjanya]

:confused:#include<stdio.h>
#include<conio.h>
void main(){
int a;
clr scr();
a=10;
a=a++ + --a;
print f("%d",a);
get ch();
}
the sol must be 21 but its showing 20 http://forum.codecal...1/confused1.gif

[WingedPanther]

This is not a tutorial: moved to the correct forum.

Do you understand the difference between a++, ++a, --a, and a--? What exactly are you trying to accomplish?

[wim DC]

WingedPanther said:

What exactly are you trying to accomplish?

It's probably an assignment, so nothing really :-P

Who said it must be 21?

What'll happen is
a++ + --a
(10 + (10-1) ) + 1... which is 20.

Quote

Do you understand the difference between a++, ++a, --a, and a--?

This is important to know / understand.

[krishna sowjanya]

thank you Mr.Panther. if we give the same at print f its giving sol as 21 if u don't mind can u please explain the difference of a++,++a,--a, and . a-- please

[Alexander]

It's a very basic operator in a language, you should know it:
Pre and Post Increment and Decrement Operators

[krishna sowjanya]

thanx mr oxano but im still in confusion about this solution y bcz when u give in print f statement its giving as 21 can plz explain the difference

[krishna sowjanya]

thank you sir i am a bit clarified but i try to understand the logic with your example its really good sol. thanku once again

[WingedPanther]

Can you post the exact code that produces 21?

[ahshan]

code to produce 21


#include<stdio.h>

int main()
{
int a=10;
a=++a + a--; //++a is pre-increment that means it increments the value by 1 before any further computation is done ans a-- is post increment i.e first //current value of a is assigned and then decrements by 1

printf("%d",a);
return 0;
}

[WingedPanther]

So really, you're asking what's the difference between:

int a=10;
    a=++a + a--;

and

a=10;
a=a++ + --a;

Correct?

I would expect one to return 22, and the other 20.