2 replies to this topic

[onus]

I wrote this program

#include<stdio.h>

int main ()

{

int a;

char * c,d;

 c="Onus";

 d="animation";

printf("\n%s",c);

printf("\n%s",d);

}

but upon compiling I got following warning

temp.c: In function ‘main’:

temp.c:7: warning: assignment makes integer from pointer without a cast

temp.c:9: warning: format ‘%s’ expects type ‘char *’, but argument 2 has type ‘int’

and when I executed it executed with following errors

./a.out 


Onus

Segmentation fault

Can some one point me as what is wrong in above and why am I getting warning?

[Alexander]

Why are you storing an array of chars into a pointer? You would initialize each string as a char array:

#include<stdio.h>
int main () {
    int a;
    char c[] = "Onus";
    char d[] = "animation";
    printf("\n%s",c);
    printf("\n%s",d);
}

[onus]

Ok.Was just trying a new way.