Sign In
Create Account
Follow Us on Twitter
Subscribe on Youtube
2
Hello
I have made a C sharp program that doing steganography ... this mean my program hide information in wav file... up to now is good
The problem is that I need now a program (I prefer window program) to compare two wav files ... those wav files are the original file and the stego file (the wav file with the hidden information)
I need this program to compare those two files and find if there is any difference between them ...
5 replies to this topic
Back to top|
|
|
#2
Posted 12 August 2010 - 03:21 PM
WingedPanther
-
- Moderators
-
- 16,831 posts
A spammer's worst nightmare
- Location:Upstate, South Carolina
- Programming Language:C, C++, PL/SQL, Delphi/Object Pascal, Pascal, Transact-SQL, Others
- Learning:Java, C#, PHP, JavaScript, Lisp, Fortran, Haskell, Others
How about BeyondCompare?
#3
Posted 12 August 2010 - 03:45 PM
prof.deedee
-
- Members
-
- 50 posts
Learning Programmer
is this one for wav files???
because when I read it said comparing folders and text files!!!
because when I read it said comparing folders and text files!!!
#4
Posted 12 August 2010 - 03:49 PM
WingedPanther
-
- Moderators
-
- 16,831 posts
A spammer's worst nightmare
- Location:Upstate, South Carolina
- Programming Language:C, C++, PL/SQL, Delphi/Object Pascal, Pascal, Transact-SQL, Others
- Learning:Java, C#, PHP, JavaScript, Lisp, Fortran, Haskell, Others
It can do binary compare of files.
#5
Posted 12 August 2010 - 04:27 PM
kresh7
-
- Members
-
- 661 posts
Programming God
Well you could do a file size compare,calculate a checksum hash or a md5 hash for the wav file and then compare it to each new wav file
#6
Posted 17 August 2010 - 06:08 AM
prof.deedee
-
- Members
-
- 50 posts
Learning Programmer
when I download the trial of BeyondCompar it is not warking !!!
when I click on it says :"the filename or directory name is incorrect "
why???
when I click on it says :"the filename or directory name is incorrect "
why???
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users
