2 replies to this topic

[csepraveenkumar]

the following code gives this error on compiling
error

struct1.c: In function ‘main’:
struct1.c:7: error: expected expression before ‘{’ token
struct1.c:8: error: expected expression before ‘{’ token

the code is

#include<stdio.h>
main(){
struct point{
int x;
int y;
} x,y;
x={1,2};
y={3,4};
printf(" %d %d %d %d\n",x.x,x.y,y.x,y.y);
}

how do i initialize the variables x and y if i don't want to initialize them where i have defined them?

[ZekeDragon]

That's because you cannot assign an initializer list to a struct that has already been instantiated. Initializer lists ONLY occur during initialization, never afterward. You can do what you're trying to do like so:

#include <stdio.h>

int main(void)
{
    struct point
    {
        int x;
        int y;
    } x = {1, 2}, y = {3, 4};

    printf("%d, %d, %d, %d\n", x.x, x.y, y.x, y.y);
}

Now to complain about your code. Use indentation! int ALWAYS comes before main(), and if you don't have any parameters for main, put in (void). Spacing, and thus readability, matters, use it.

EDIT: If you don't want to initialize them where you have defined them you'll have to do it all individually. I've seen some hacks that will perform struct initialization within a loop, but I don't recommend it personally.

[Aereshaa]

Actually in c99 you can in fact assign structs, and make struct literals. Like this:

int main(void){
 struct t {int x} a;
 a = (struct t){10};
}