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$exist = $_POST['exist'];
$body = $_POST['body'];
if($exist == true){
$rBody = $body;
} else {
$rBody = "rvar=" . $body;
}
ty in advance.
2 replies to this topic
#1
Posted 18 December 2009 - 10:44 AM
mayo
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- Members
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- 15 posts
Newbie
Hi. I'm writing a very simple script. Im recieving 2 variables, body and exist, with the POST method from a flash application. Then I wish to create a 3rd variable named rBody, who will equal body if exist is true, and if exist is false, it will add " rvar= " in the beginning, then body. This is the code I used (didn't work):
ty in advance.
ty in advance.
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#2
Posted 18 December 2009 - 11:46 AM
amrosama
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- Members
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- 8,674 posts
Writes binary right handed and hex left handed
this should fix it
$_POST and $_GET variables are usually strings unless its set from inside PHP like
$_POST['var']=true;
$exist = $_POST['exist'];
$body = $_POST['body'];
if($exist == 'true'){
$rBody = $body;
} else {
$rBody = "rvar=" . $body;
}
$_POST and $_GET variables are usually strings unless its set from inside PHP like
$_POST['var']=true;
yo homie i heard you like one-line codes so i put a one line code that evals a decrypted one line code that prints "i love one line codes"
eval(base64_decode("cHJpbnQgJ2kgbG92ZSBvbmUtbGluZSBjb2Rlcyc7"));
www.amrosama.com | the unholy methods of javascript
