5 replies to this topic

[suricata]

I have this code:

typedef struct {

	unsigned short a, b, c, d, e, f, g, h;

}est_;

est_ est[512];

I want to know if there is a way to access to a variable of est by this kind of thing:

var='a';

est[1].[var]=0;

Yes, it doesnt work but, there is a way to do such a thing?

Greetings!

[ZekeDragon]

You're trying to call a variable name as a variable in itself, and no, you can't do that. It's very easy to do this:

est[1].a = 0;

But you can't try and use the value of a variable as the name of another variable, it's simply impossible. I'm not even sure why you'd want to try and do this, is there some reason for it?

[suricata]

Ok the question is that i need it inside a function . . .

int f_mov(char uno, char dos, int op, int pid)

{

	if(oneop(op) || op == O_NULL)

		return ERROR;

        /*Here, i want to do something like:

        est[pid].[uno]=est[pid].[dos];

        or something to avoid a lot of comparisions*/

	return OK;

}

[marwex89]

ZekeDragon said:

You're trying to call a variable name as a variable in itself, and no, you can't do that. It's very easy to do this:

est[1].a = 0;

But you can't try and use the value of a variable as the name of another variable, it's simply impossible. I'm not even sure why you'd want to try and do this, is there some reason for it?

Mwoahaha wanna bet? :rules: Well, technically you are right, but this might help you suricata:

typedef struct {
       unsigned short a, b, c, d, e, f, g, h;
    }est_;
    est_ est[512];
      
    int i, a;
    unsigned short* p_est[512][8];
         
    for(a = 0; a < 512; ++a)
    {
    for(i = 0; i < 8; ++i)
    {
        switch(i)
        {
            case 0:
                p_est[a][i] = &est[a].a;
                break;
            case 1:
                p_est[a][i] = &est[a].b;
                break;
            case 2:
                p_est[a][i] = &est[a].c;
                break;
            case 3:
                p_est[a][i] = &est[a].d;
                break;
            case 4:
                p_est[a][i] = &est[a].e;
                break;
            case 5:
                p_est[a][i] = &est[a].f;
                break;
            case 6:
                p_est[a][i] = &est[a].g;
                break;
            case 7:
                p_est[a][i] = &est[a].h;
                break; 
        }                   
    }
    }

As you can see we now have a two dimensional array of pointers.
To access for example est[23].g we would do:

*p_est[23][6] = 5; /* Set est[23].g to 5 */

So to fill every est (all 512) a,b,c,d,e,f,g,h with fives you could do:

    for(a = 0; a < 512; ++a)    
        for(i = 0; i < 8; ++i)
            *p_est[a][i] = 5;       

[suricata]

Thanks for the replies. . . . two dimension arrays is the solution :) (thank you marwex89)

Greetings!

[marwex89]

No problem :)