<html>
<head>
</head>
<body>
<?php
$con = mysql_connect('localhost','*****','*****');
if (!$con) {
die ('could not connect: ' . mysql_error());
}
$select_db=mysql_select_db("*****", $con);
if(!$select_db) {
die ('could not connect to db: ' . mysql_error());
}
$username = $_POST['username'];
$password = $_POST['password'];
$sql="SELECT username FROM LogIn WHERE username=".$username." and password=".$password;
$err=mysql_error();
$result=mysql_query($sql);
if(!$sql) {
echo $err;
}
if(!mysql_num_rows($result)) {
echo "username or password is wrong";
}
else {
echo "Login successful";
}
?>
</body>
</html>
the problem is Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource. on line 32 wich is if(!mysql_num_rows($result)). thanks alot :)


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