5 replies to this topic

[jamesw]

Language is Java and I have three integers ( t,r,s ). And on every one of them there will be a value.
algorithm chooses a smaller one of the values of variables t and r and places it in the variable s.
but how the algorithm does behave if int t and r have same value, both are for example 6?

[Aereshaa]

Since both have the same value, the result is the same whichever you choose.

[jamesw]

Thank you. Here it is, I made this. So; variable s will get a value 6. it really
gets a value 6, because "else s=r" - right.

   public class static void main(String [] args) {
   	
	int t = 6, r = 6, s;	

	    if (t<r) s=t;

	    else s=r;    

2. and a little problem;

if x=8

((x / 2) == 0);

but is this sentence right; ((x % 3) == 0); ( * % IS BECAUSE mod, BUT IS == 0 RIGHT? *)

3.

and I want to say, that the int 10 has two numbers, 1 and 0. Is my solution right?
I think 10 is two letters and it is smaller than three letters 100. But maybe this is wrong.

(((x > 10) && (x < 100)) || ((x < -10) && (x > -100)));

Edited by Jaan, 07 November 2008 - 02:26 AM.
Please use code tags when you're posting your codes!

[LordIzuriel]

Yea, your solution to put the smallest of the two ints into 's' is correct although you may want to code a bit neater than that for readability.

2) I'm not quite sure what you asking here, however I'm going to take a crack at what I think you are looking for. x % 3 will never = 0 if x = 8, but x % 2 will, and you have the correct code for that...

int x = 8;

if ((x % 2) == 0)
   // do something

3) Once again, not 100% sure what you are asking for, but I'm taking a crack at what I think you are looking for. For the most part, you are correct, however... (x >= 10) and (x <= -10) so that you include the number 10 in that, because 10 is two digits as well.

[jamesw]

Thank you.

2.

I want to write how the claim would be output.? according to it
x / 3 would be;
((x % 3) != 0); ( * % IS BECAUSE mod, else it would be x / 3 )

I changed == TO != , because the result is not 0

Code:

if x=8

((x / 2) == 0);


3.

same thing here; I want to write how the claim would be output.
So the int 10 has two numbers, 1 and 0.
[B in the number 10 there are exactly two numbers;
[/B]

Code:

(((x > 10) && (x < 100)) || ((x < -10) && (x > -100)));