6 replies to this topic

[mindsurfer]

hi ...
i am trying to find the smallest and the largest of four numbers.. but if,for example, i input a value like 100000000 , it shows me a result "Largest number is 1e+009".. can someone please tell me why it doesn't show "1000000000".. sorry for asking this kind of question as i am new to C++..

someone advised me to use <limits.h> but i dont know how to use that in my code... some one please help me..

# include <iostream>


using namespace std;


int main()


{

    float number1,number2,number3,number4;


    cout << "Enter the value of number 1 : ";

    cin >>number1;


    cout << "Enter the value of number 2 : ";

    cin >>number2;


    cout << "Enter the value of number 3 : ";

    cin >>number3;


    cout <<"Enter the value of number 4 : ";

    cin >>number4;


    if (number1 > number2 && number1 > number3 && number1 > number4)

        cout << "Largest number is : " <<number1 <<endl;


    else if (number2 > number3 && number2 > number4)

        cout << "Largest number is : " <<number2 <<endl;


    else if (number3 > number4)

        cout << "Largest number is : " <<number3 <<endl;


    else

        cout << "Largest number is : " <<number4 <<endl;


    if (number1 < number2 && number1 < number3 && number1 < number4)

        cout << "Smallest number is : " <<number1 <<endl;


    else if (number2 < number3 && number3 < number4)

        cout << "Smallest number is : " <<number2 <<endl;


    else if (number3 < number4)

        cout << "Smallest number is : " <<number3 <<endl;


    else

        cout << "Smallest number is : " <<number4 <<endl;


    return 0;


}

Thanks in advance..

[G_Morgan]

Using floats you will have to use format modifiers on the output stream to change it from standard form. 1e+009 is the equivalent of the mathematical equation 1 x 10^9. Look up formatted output.

BTW I'd have done the problem slightly differently.

float numbers[4] = {145465, 3243254, 236567, 234343658};
float largest = numbers[0];
float smallest = numbers[0];
for(int i = 1; i <= 4; i++) {
    if(numbers[i] > largest)
        largest = numbers[i];
    if(numbers[i] < smallest)
        smallest = numbers[i];
}

cout << "The largest number is " << largest << endl;
cout << "The smallest number is " << smallest << endl;

Another potential modification is doing something like

int number_terms;
cin >> number_terms;
float numbers[number_terms];
for(int i = 0; i < number_terms; i++) {
    cin >>  numbers[i];
}

This way the first argument states how many numbers you are reading.

//edit - look at this Handout - Floating point output format //

[G_Morgan]

BTW, if you have any questions about anything I've posted above just ask. It can be easy to forget how annoying all this stuff was when we all started.

[lord_guxtavo]

from my experience, it would be easier if you made an array that captures the 4 numbers, then use whatever method you like to put them in ascendant/descendant order, and display the top and the bottom one. You could've written much less code :)

[kkelly]

I believe this is an exercise in insertion. The previous post is a good idea, or possibly a binary tree.

[mokszyk]

What about:

cout.precision(x) //where x , means number

Hmm?

[DevilsCharm]

I guess C++ automatically deals with large numbers in scientific notation? I know that Python divides numbers and uses remainders instead of decimals... kind of weird but that's how it works.