3 replies to this topic

[John]

1) Read a line in the console or from a file?
2) No idea
3) Create a loop for the length of the array, the get the length of each element in the array and add it to the previous value, maybe something like this:

int size = 0;
for(int i = 0; i < myArray.length(); i++){
size = myArray[i].length() + size;
}

4) Pretty much just another loop that checks every letter of every word in every element in the array and adds the values to the 2D array, that should get you started but if you need more help let me know....but i dont think there is a native function to do this

[John]

For 4, im not sure why you would want to use a two dimensional array, but if I understood the functionality correctly this should do 3 and 4

package general;

public class ArrayFunctions {

	private String[] myArray = new String[] {"john", "steve", "jordan", "lauren", "tom", "bobby", "bill", "andrew"};
	private String[] letters = new String[] {"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"};
	private int totalLength = 0;
	private Integer[] ofEachChar = new Integer[26];
	
	public ArrayFunctions(){
		TotalLength();
		AmountOfEachChar();
	}
	
	public void TotalLength(){
		for(int i = 0; i < myArray.length; i++){
			totalLength = myArray[i].length() + totalLength;
		}
		
		System.out.println("The character length of the array is " + totalLength);
	}
	
	public void AmountOfEachChar(){
		//check each element
		for(int i = 0; i < myArray.length; i++){
			//check each word
			for(int p = 0; p < letters.length; p++){	
				//Set each element in "ofEachChar" to 0 to avoide a NullPointerException
				if(ofEachChar[p] == null){
					ofEachChar[p] = 0;
				}
                                //and every letter of each word
				for(int j = 0; j < myArray[i].length(); j++){
                                        //if the j'th character is the same as the p'th letter in the alphabet
					if(String.valueOf(myArray[i].charAt(j)).toUpperCase().equals(letters[p])){
                                                        //add 1 to the p'th ofEachChar element
							ofEachChar[p] = 1 + ofEachChar[p];	
					}
				}
			}
		}	
		//Print the results
		for(int i = 0; i < letters.length; i++){
			System.out.println("There are " + ofEachChar[i] + " " + letters[i] + "'s");
		}
	}
	
	public static void main(String[] args){
		new ArrayFunctions();
	}
	
}