if greater than but less than

[opencircles]

i hate not figuring out on my own but im lost

a = input("please enter your age: ")

if a >= 18:
    print"you may enter"
else:
    print"you are to young."
if a > 110:
    print "invalid age entered"


raw_input()

obviously if anythin over 110 is input then it says ivalid age entered but also says you may enter. how do i write if a >= 18 but < 110?

[Hot_Milo23]

Posted via CodeCall Mobile
i cant check this atm, but off the top of my head, you could try:
if a>18 && a<110....
or it could be only one &.
hope that helps.

[opencircles]

wut does the & stand for in python?

and think for the post i will try it in th a.m.

[Hot_Milo23]

Posted via CodeCall mobi dnt quote me, but it basicly means "and"?

[opencircles]

ok thank you

[TkTech]

You're getting confused with C. In C, && is a logical and, whereas a single & is a bitwise and.

In python, its just 'and', so:

if (a >= 18) and (a <= 110):
   print "Zomg!"

[Hot_Milo23]

haha, of course.
oops.
thx

[Vswe]

You should do it like this instead(using an elif block):

 
a = input("please enter your age: ")
 
if a > 110:
    print "invalid age entered"
elif a >= 18:
    print "you may enter"enter"
else:
    print "you are to young."
 
 
 
raw_input()

[UnknownFear]

@Vswe: But take out the extra "enter"

a = input("please enter your age: ")
 
if a > 110:
    print "invalid age entered"
elif a >= 18:
    print "you may enter"
else:
    print "you are to young."

raw_input()

[Vswe]

yes of course. A typing error while moving them around with copy/paste.