Encryption using Random!?

[TcM]

So because the random number is in the encrypted message it's self it is automatically the public key?

[John]

Originally Posted by TheComputerMaster

So because the random number is in the encrypted message it's self it is automatically the public key?

No, I just chose the random number as the public key because it just seems more public than the 66. Your method isn't exactly how public key encryption works.

[TcM]

Hmm I kinda understand but still a little confused, thanks for the little clarification

[WingedPanther]

Originally Posted by TheComputerMaster

What do you mean?

In your original message, you had the following:

A -> (ASCII*66)+random number

A = 65
Random = 125
Intermediate code: (65*66)+125=4415

Final code: 1454152

At this point, you have embedded 125 into the final code in a predictable way, making recovery of the original value easy.

[WingedPanther]

Dual key encryption works by using some tricks from number theory related to prime powers. It is NOT for the mathematically faint of heart!