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No, I just chose the random number as the public key because it just seems more public than the 66. Your method isn't exactly how public key encryption works.
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In your original message, you had the following:
A -> (ASCII*66)+random number A = 65 Random = 125 Intermediate code: (65*66)+125=4415 Final code: 1454152 At this point, you have embedded 125 into the final code in a predictable way, making recovery of the original value easy.
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Dual key encryption works by using some tricks from number theory related to prime powers. It is NOT for the mathematically faint of heart!
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