So because the random number is in the encrypted message it's self it is automatically the public key?
Hmm I kinda understand but still a little confused, thanks for the little clarification![]()
In your original message, you had the following:
A -> (ASCII*66)+random number
A = 65
Random = 125
Intermediate code: (65*66)+125=4415
Final code: 1454152
At this point, you have embedded 125 into the final code in a predictable way, making recovery of the original value easy.
Dual key encryption works by using some tricks from number theory related to prime powers. It is NOT for the mathematically faint of heart!
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