Okay..I'm going to show y'all how to show your images.. those which are in your DB
It's very very simple.. so..
First of all we must connect to our database
Code:
<?php
$username = "";
$password = "";
$host = "localhost";
$database = "";
$username = ""; - It's your database's username
$password = ""; - It's your database's password
$host = "localhost"; - It's your database's host, usually it's localhost but it can be something else also
$database = ""; - It's your database
Now let's connect to the database
Code:
@mysql_connect($host, $username, $password) or die("Can not connect to database: ".mysql_error());
@mysql_select_db($database) or die("Can not select the database: ".mysql_error());
@mysql_connect($host, $username, $password) or die("Can not connect to database: ".mysql_error()); - This connects to your database
@mysql_select_db($database) or die("Can not select the database: ".mysql_error()); - This will select your database
Now let's get our id
It will get a id from an URL. blabla.com
So.. your id will be 3 and it will show an image which id is 3
Code:
if(!isset($id) || empty($id)){
die("Please select your image!");
}else{
if(!isset($id) || empty($id)){ - If this ID in your url is empty like ?id= of if it's not even set
die("Please select your image!"); - lets display an error
}else{ - But if it is set let's continue with showing our image

Code:
$query = mysql_query("SELECT * FROM tbl_images WHERE id='".$id."'");
$row = mysql_fetch_array($query);
$content = $row['image'];
$query = mysql_query("SELECT * FROM tbl_images WHERE id='".$id."'"); - Now let's select the blob from the table where id is $id (for example: 3)
$row = mysql_fetch_array($query); - Let's gather our info about image which id is $id into one variable
$content = $row['image']; - Get's the blob from our table
Now let's display our image
Code:
header('Content-type: image/jpg');
echo $content;
}
header('Content-type: image/jpg'); - This tells to the browser and to the server that this file will be a jpg file
echo $content; - This will display our blob..
} - Ends else
Okay.. now here's our full script.
Code:
<?php
$username = "";
$password = "";
$host = "localhost";
$database = "";
@mysql_connect($host, $username, $password) or die("Can not connect to database: ".mysql_error());
@mysql_select_db($database) or die("Can not select the database: ".mysql_error());
$id = $_GET['id'];
if(!isset($id) || empty($id)){
die("Please select your image!");
}else{
$query = mysql_query("SELECT * FROM tbl_images WHERE id='".$id."'");
$row = mysql_fetch_array($query);
$content = $row['image'];
header('Content-type: image/jpg');
echo $content;
}
?>
It works perfectly 

Enjoy 
If you have questions then please feel free to ask