Help me *OpenFileDialog*

[Tuve2]

I'm trying to make a "OpenFileDialog".
But I get a error.

        private void button1_Click(object sender, EventArgs e)
        {
            Stream myStream = null;
            OpenFileDialog openFileDialog1 = new OpenFileDialog();

            openFileDialog1.InitialDirectory = "c:\\";
            openFileDialog1.Filter = "txt files (*.txt)|*.txt|bat files (*.bat)|*.bat|All files (*.*)|*.*";
            openFileDialog1.FilterIndex = 2;
            openFileDialog1.RestoreDirectory = true;

            if (openFileDialog1.ShowDialog() == DialogResult.OK)
            {
                try
                {
                    if ((myStream = openFileDialog1.OpenFile()) != null)
                    {
                        using (myStream)
                        {
                            // Insert code to read the stream here.
                        }
                    }
                }
                catch (Exception ex)
                {
                    MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
                }
            }
        }

Error:

The type or namespace name 'Stream' could not be found (are you missing a using directive or an assembly reference?)

Can somebody help me?

[Jordan]

Try using the full namespace:

System.IO.Stream myStream = null;

[Tuve2]

Thanks!

[Tuve2]

Do you know how I can see the file in a window? now? When I have opened it.

[Jordan]

I'm not sure I understand. You should see all the files in the current directory.

[Tuve2]

nvm