Please help me I have a very big problem!!

[Mathematix]

I want to post solutions for all, but I won't. The leap year one is very, very easy, though! What is unique about a leap year? It is divisible by four exactly, so if:

if(year % 4 == 0)
   // we have a leap year!
else
   // we don't have a leap year.

I will contain myself now...

[WingedPanther]

The catch being that if it is divisible by 100, it must also be divisible by 400 to be a leap year.

[ArekBulski]

Indeed, Winged. This is why I gave a hint to look into Wikipedia. Mathematix, you earned some -rep for yourself. Giving wrong (unconfirmed) intel is as good as kicking someone's face.

See some pseudocode: Leap year - Wikipedia, the free encyclopedia

[Mathematix]

Indeed, Winged. This is why I gave a hint to look into Wikipedia. Mathematix, you earned some -rep for yourself. Giving wrong (unconfirmed) intel is as good as kicking someone's face.

See some pseudocode: Leap year - Wikipedia, the free encyclopedia

And I've had to -rep you right back. Had to because you didn't provide a proper definition of your own nor solution.

I'll post a solution when I get home tonight - it's easy enough.

[ArekBulski]

Here it is. Is this what you would like to see? Honestly, I prefer the DateTime class to do the job. Just between you and me, I do not like to give people cooked-ready solutions. I prefer just to give clues. Oh, forgot to add that this is C#.

static void Main(string[] args)
{
    for (int year = 1980; year < 2009; year++)
    {
        Console.WriteLine("IsYearLeap says {0} when DateTime says {1}",
            IsYearLeap(year), DateTime.IsLeapYear(year));
    }
}

private static bool IsYearLeap(int year)
{
    if (year % 400 == 0)
        return true;
    if (year % 100 == 0)
        return false;
    if (year % 4 == 0)
        return true;
    return false;
} 

[Mathematix]

Here it is. Is this what you would like to see? Honestly, I prefer the DateTime class to do the job. Just between you and me, I do not like to give people cooked-ready solutions. I prefer just to give clues. Oh, forgot to add that this is C#.

static void Main(string[] args)
{
    for (int year = 1980; year < 2009; year++)
    {
        Console.WriteLine("IsYearLeap says {0} when DateTime says {1}",
            IsYearLeap(year), DateTime.IsLeapYear(year));
    }
}

private static bool IsYearLeap(int year)
{
    if (year % 400 == 0)
        return true;
    if (year % 100 == 0)
        return false;
    if (year % 4 == 0)
        return true;
    return false;
} 

That isn't the solution! I'll do it later.

[Mathematix]

At last I had some time to knock up some code. I used VC++ 2008 to build as those who are curious can build the code without having to purchase a nice IDE!

#include <stdio.h>
#include <string.h>
#include <malloc.h>

#define GEORGIAN_LEAP 4
#define NOT_LEAP_YEAR 100
#define IS_LEAP_YEAR 400

#define HAS_DAYS_31 31
#define HAS_DAYS_30 30
#define HAS_DAYS_28 28
#define HAS_DAYS_29 29

const char* months[] = 
{
	"January",
	"February",
	"March",
	"April",
	"May",
	"June",
	"July",
	"August",
	"September",
	"October",
	"November",
	"December"
};

struct monthDays
{
	char* mths;
	int numdays;
};

int main()
{

	// We initialise all months apart from Febuary until we determine a leap year!
	monthDays yearMonths[12];
	for(int i = 0; i < 12; i++)
	{
		yearMonths[i].mths = (char*)months[i];
		if(i == 1) // DON'T set February number of days yet!
		{
			continue;
		}

		// Fill the months and associated days!
		if(strstr(yearMonths[i].mths, months[0]) ||		// January
		   strstr(yearMonths[i].mths, months[2]) ||		// March
		   strstr(yearMonths[i].mths, months[4]) ||		// May
		   strstr(yearMonths[i].mths, months[6]) ||		// July
		   strstr(yearMonths[i].mths, months[7]) ||		// August
		   strstr(yearMonths[i].mths, months[9]) ||		// October
		   strstr(yearMonths[i].mths, months[11]))		// December
		{
			yearMonths[i].numdays = HAS_DAYS_31;
			continue;
		}

		if(strstr(yearMonths[i].mths, months[3]) ||		// April
		   strstr(yearMonths[i].mths, months[5]) ||		// June
		   strstr(yearMonths[i].mths, months[8]) ||		// September
		   strstr(yearMonths[i].mths, months[10]))		// November
		{
			yearMonths[i].numdays = HAS_DAYS_30;
			continue;
		}

		printf("%s has %d days.\n", yearMonths[i].mths, yearMonths[i].numdays);
	}

	// seed the year and days entered by user.
	int year = 0, days = 0;

	puts("Enter a year: ");
	scanf("%i", &year);
	puts("Enter the days: ");
	scanf("%i", &days);

	int daysSum = 0;
	int exactDate = 0;
	char* currentMonth = (char *) malloc(sizeof(char) * 30);

	if((year % GEORGIAN_LEAP) == 0)	// We've fulfilled the condition for a 'Georgian leap'
	{

		if(((year % NOT_LEAP_YEAR) != 0) || ((year % IS_LEAP_YEAR) == 0))	// Other conditions fulfilled.
		{
			yearMonths[1].numdays = HAS_DAYS_29;	// Feb has 29 days in a leap year.
			printf("We have a leap year! (%d)\n", year);

			// Work out the date.
			int i = 0;
			while(i < 11)
			{
				if((daysSum + yearMonths[i].numdays) >= days)
				{
					break;
				}

				daysSum += yearMonths[i].numdays;

				i++;
			}

			currentMonth = yearMonths[i].mths;
			if((days - daysSum) == 0)
				exactDate = 31;
			else
				exactDate = days - daysSum;

			printf("It is %s %d\n", currentMonth, exactDate);
		}
	}
	else
	{
		yearMonths[1].numdays = HAS_DAYS_28;	// Feb has 28 days in a common year.
		printf("We do not have a leap year, alas... (%d)\n", year);

			// Work out the date.
			int i = 0;
			while(i < 12)
			{
				if((daysSum + yearMonths[i].numdays) >= days)
				{
					break;
				}

				daysSum += yearMonths[i].numdays;

				if(i < 11)
					i++;
			}

			currentMonth = yearMonths[i].mths;
			if((days - daysSum) == 0)
				exactDate = 31;
			else
				exactDate = days - daysSum;

			printf("It is %s %d\n", currentMonth, exactDate);
	}
}

I've left it monolithic so that it's easier to work through. given that this is a homework assignment I've made the commenting rather scant forcing the OP to do some significant analysis. Am happy to take questions, though.

Also feel free to point out any bugs and I might fix them.

[ArekBulski]

He he, actually none of our solutions is exactly an answer. You see, this is a Managed C++ section and neither of our code is in it.

[Mathematix]

He he, actually none of our solutions is exactly an answer. You see, this is a Managed C++ section and neither of our code is in it.

I beg to differ. If the OP can't handle such problems, I doubt they know the difference between managed and non-managed C++ and have actually posted on the wrong forum.

Secondly given the it was mentioned at the end that they can only use loops, arrays and if-statements, none of those are specific to managed code.