use GUI application to be used to test Kindergarden children on the alphabet (‘A’-‘Z

[Shaddix]

normally we don't give you the code here, but as it's a simple program it might be easier to explain everything by code

import java.util.Random;
import java.util.Scanner;

public class Alphabet {
	//We declare the random generator globally
	private Random generator = new Random();
	
	//Here we will remember what the index was of the letter we asked
	private int askedLetterIndex;
	
	//Here we declare the alphabet
	private char[] alphabet = {'a','b','c','d','e','f','g','h'
			,'i','j','k','l','m','n','o','p','q'
			,'r','s','t','u','v','w','x','y','z'};
	
	//This function will get you a random number from our alphabet
	private char getRandomLetter(){
		askedLetterIndex = generator.nextInt(24);
		return alphabet[askedLetterIndex];
	}
	
	//This will check the answer of the user, it returns True if the answer was correct and False if it was incorrect
	private Boolean checkAnswer(char answer){
		if (alphabet[askedLetterIndex + 1] == answer){
			return true;
		}else{
			return false;
		}
	}
	
	//This method will do the test 
	//This is a console application, so for a GUI application you'll have to rewrite this method
	public void doTest(){
		//The scanner will be used to read the answer of the user
		Scanner in = new Scanner(System.in);
		
		//Here we will stock the answer of the user
		char answer;
		
		//This will ask the user a letter for 10 times
		for(int i = 0; i < 10; i++){
			System.out.println("What letter comes afther '" + getRandomLetter() + "' ?");
			answer = in.next().charAt(0);
			
			if(checkAnswer(answer)){
				System.out.println("Correct!");
			}else
				System.out.println("Wrong!");
		}
	}
	
	//Run the program
	public static void main(String[] args) {
		Alphabet a = new Alphabet();
		a.doTest();
	}
}

This is a console application, but it shows you how to do this kind of programs

[funjoke88]

this is the part of code only right ?but i not sure how to use gui application for this question ,can you help me pls

[funjoke88]

hello can you use GUI application to write out the code for this question ?pls help me !

[wim DC]

Common, show some effort.
Give us the code you would use to create a GUI class. it will basicly need 2 components, a JLabel and a JTextfield. Every System.out.println() should be turned into a method like FrameClass.setLabelText(text)

And the "in.next()" is replaced by a JTextfield.

To let the textfield react on the user's 'ENTER' use:

textfield.addKeyListener(new KeyListener(){
        public void keyPressed(KeyEvent e){/*Empty*/ }
        public void keyReleased(KeyEvent e){/*Empty*/}
        public void keyTyped(KeyEvent e){
                if(e.getKeyChar() == KeyEvent.VK_ENTER){
                    String text = textfield.getText();
                    alphabet.checkAnswer(text)
                }
            }

        });

Or you could use a button instead

[funjoke88]

hello may i know is this a full source code for gui application in this question ?thanks for helping me ...

textfield.addKeyListener(new KeyListener(){
        public void keyPressed(KeyEvent e){/*Empty*/ }
        public void keyReleased(KeyEvent e){/*Empty*/}
        public void keyTyped(KeyEvent e){
                if(e.getKeyChar() == KeyEvent.VK_ENTER){
                    String text = textfield.getText();
                    alphabet.checkAnswer(text)
                }
            }

        });

[wim DC]

No, it only adds a listener to a textfield so when you are typing in the textfield and push 'Enter' something happens.

[funjoke88]

can i have the full code of it ?because i really dunoo how to do this question ,shaddix

[funjoke88]

hello may i know the solution of gui application ?i really need the source code of this question .pls help me shaddix

[funjoke88]

hello ,the code u given are tested .but the alphabet is repeated for some .and the question request that no alphabet is to be repeated .so how 2 solve this problem ?shaddix thanks

[wim DC]

Got this from another post on the forums. Fits so perfectly:

While( !User.hasAnswer )
{
     User.askQuestion();

     if( User.postCode && User.putForthEffort )
     {
          CodeCallMembers.Help();
          User.hasAnswer = true;
     }
     else
     {
          CodeCallMembers.Laugh();
     }
}