Python, self replicating scripts

[Deep fried ice-cream]

I am new to programming but I have been having a muck around in python.
My current project is a self replicating code, however this requires one command that I cant find anyware, the project consists of two scripts, one to start the thing off and the other copies it self.
However I don’t know the command to make one python script run another
P.S. G:\ is a flash drive

the starter:

def write(name, text):
    out_file = open(name, "w")
    out_file.write(text)
    out_file.close()

def read(name):
    in_file = open(name, "r")
    text = in_file.read()
    in_file.close()
    return text

text = 'def write(name, text):\n    out_file = open(name, "w")\n    out_file.write(text)\n    out_file.close()\ndef read(name):\n    in_file = open(name, "r")\n    text = in_file.read()\n    in_file.close()\n    return text\nwhile 1 == 1:\n    try:\n        this_name = read("name_list")\n    except IOError:\n        write("name_list", "0")\n    this_name = "0"\n    this_name = int(this_name)\n    next_name = str(this_name + 1)\n    this_name = str(this_name)\n    write(next_name + ".py", read(this_name + ".py"))\n    write("name_list", next_name)'
try:
    num = int(read('G:/bomb/name_list'))
    num = str(num + 1)
except IOError:
    num = "0"
write('G:/bomb/' + num + ".py", text)
#run ('G:/bomb/' + num + ".py")

and the main thing:
P.S. this is made by the first one.

def write(name, text):
    out_file = open(name, "w")
    out_file.write(text)
    out_file.close()
def read(name):
    in_file = open(name, "r")
    text = in_file.read()
    in_file.close()
    return text
while 1 == 1:
    try:
        this_name = read("name_list")
    except IOError:
        write("name_list", "0")
        this_name = "0"
    this_name = int(this_name)
    next_name = str(this_name + 1)
    this_name = str(this_name)
    write(next_name + ".py", read(this_name + ".py"))
    write("name_list", next_name)
    #run(next_name + ".py")