text program

[Reigan]

I need code, who take some string of character, and to compare that a .txt file.
example:

string = "qwe"
.txt file = ''axcbhyqweklmnpouyxsqwelkopyqqwesd''
_____________((7)__________(20)_____(29)

I need then program find in this text file a letters: ''qwe'' and call the number of that place, where this letter start in text.

result must be:
7, 20, 29

please help me.

[Xav]

To get the data, use System.IO.File.ReadAllText("FullPathNameOfTextFile Here.txt"). You can use an "include" statement here. To search for the string, look at the methods inside the string. Try Contains() to see if the string exists, then use IndexOf() to get the index of each. Remove the occurrence in a separate copy of the text, then search again to find the next one.

[WingedPanther]

If you are using C++, there are some string functions that can do this for you quite easily. If you are using C, it will be a bit trickier. Not knowing the language or what you've done so far, it's tough to help.

[R-G]

I don't know which computer programming language you would prefer for a solution of such a problem. I hope that this source software code algorithm written in the computer programming language Assembly will fit your wishes.

.xlist
include         stdlib.a
includelib      stdlib.lib
.list

wp              textequ <word ptr>

dseg            segment para public 'data'

StrPtr          dword   ?
FileName        dword   ?
LineCnt         dword   ?

FVar            filevar {}

InputLine       byte    1024 dup (?)
dseg            ends


cseg            segment para public 'code'
assume  cs:cseg
ds:dseg


ReadLn          proc
push    es
push    ax
push    di
push    bx

lesi    FVar
mov     bx
0
ReadLp:         fgetc
jc      EndRead

cmp     al
cr
je      ReadLp
cmp     al
lf
je      EndRead

mov     InputLine[bx]
al
inc     bx
jmp     ReadLp


EndRead:        mov     InputLine[bx]
0
pop     bx
pop     di
pop     ax
pop     es
ret
ReadLn          endp


Main            proc
mov     ax
dseg
mov     ds
ax
mov     es
ax
meminit

argc
cmp     cx
2
je      GoodArgs
print
byte    "Usage: Software_name 'string' filename"
cr
lf
0
jmp     Quit

GoodArgs:       mov     ax
1
argv
mov     wp StrPtr
di
mov     wp StrPtr+2
es

mov     ax
2
argv
mov     wp Filename
di
mov     wp Filename+2
es


mov     ax
0
mov     si
wp FileName
mov     dx
wp FileName+2
lesi    Fvar
fopen
jc      BadOpen


mov     wp LineCnt
0
mov     wp LineCnt+2
0
SearchLp:       call    ReadLn
jc      AtEOF


add     wp LineCnt
1
adc     wp LineCnt+2
0


lesi    InputLine
mov     dx
wp StrPtr+2
mov     si
wp StrPtr
strstr
jc      SearchLp


printf
byte    "Found '%^s' at line %ld\n"
0
dword   StrPtr
LineCnt
jmp     SearchLp


AtEOF:          lesi    FVar
fclose
jmp     Quit

BadOpen:        printf
byte    "Error attempting to open %^s\n"
cr
lf
0
dword   FileName


Quit:           ExitPgm
Main            endp

cseg            ends

sseg            segment para stack 'stack'
stk             db      1024 dup ("stack   ")
sseg            ends

zzzzzzseg       segment para public 'zzzzzz'
LastBytes       db      16 dup (?)
zzzzzzseg       ends
end     Main

[Reigan]

How to get amount of character from .txt file in c++?

[shibbythestoner]

Originally Posted by Reigan

How to get amount of character from .txt file in c++?

If you mean to count all characters, you could probably just read each line, add them together into one string, and use length():

#include<iostream>
#include<fstream>
#include<string>
using namespace std;
int main(int argc,char *argv[]){
  string fileContents="",tempContents="";
  ifstream readFile();
  readFile.open("file_name.txt");
  while(!readFile.eof()){
    getline(readFile,tempContents);
    fileContents+=tempContents;
  }
  cout<<"The amount of characters in the file should be: ";
  cout<<fileContents.length();
  cin.ignore();
  return 0;
}

[Xav]

Or, you could just use an integer variable to count the lines.