char * and char[] problem

[Anirban Chakraborty]

I was supposed to pass a (char * string1) as an argument to a method.
where it (the string) is supposed to be assigned to another (char * string2)...
The compiler gave segmentation fault.

whereas if I tried to pass the (char * string1) as the argument to the method and the char string2[16] the compiler gave out
"incompatible types in assignment of `char*' to `char[16]".

I just don't have any more idea left with me to do what I am supposed to do.

[v0id]

Show us the code, which you think produces the segfault. It could be you're using the pointers wrong. You could also step through your program using a debugger.

[Anirban Chakraborty]

typedef const char * String;
// class declaration
private:
String fileName;
public:
void bas_setfn(String Filename){
fileName = Filename;
}else; // Throw an error class that will put up an alert on the screen "FileName Should be less than 15 chars"
return;
}

The actual code is a bit too long.
is there any way to pass a char array of finite length as a method argument.

[v0id]

I tried putting what you did show me into a class, and it compiles and runs just fine, without any errors.

#include <iostream>

typedef const char * String;

class Example
{
        private:
                String filename;
        public:
                void bas_setfn(String filename)
                {
                        this->filename = filename;
                }
};

int main()
{
        Example obj;
        String str = "Hello, World!";

        obj.bas_setfn(str);

        return 0;
}

[Anirban Chakraborty]

It did...
Thanks a lot...

[Anirban Chakraborty]

I tried it with the constructor too..... It didn't work
So I did this one...

for(int i=0; i < 15 && Filename[i] != '\0'; i++)
fileName[i] = Filename[i];
fileName[i] = '\0';