need urgent help finding parce error!!!

[siren]

Sorry for the minor problem but I need help!! I need to hand in this program in a few hours but I can't seem to find the parce error!!!

#include<stdio.h>
#include <stdlib.h>
#include <time.h>

main()
{   
  int a;
  int num[3][3];
  srand((unsigned)time(NULL));
  a = rand() % (7 + 1);      /* getting random numbers 0-7*/
 
  switch(a){
  case 0:     /* if a=0 and so on*/
    num[3][3]={{8, 1, 6}, {3, 5, 7}, {4, 9, 2}};
    printf("%d", num[3][3]);
    break;
  case 1:
    num[3][3]={{4, 3, 8}, {9, 5, 1}, {2, 7, 6}};
    printf("%d", num[3][3]);
    break; 
  case 2:
    num[3][3]={{2, 9, 4}, {7, 5, 3}, {6, 1, 8}};
    printf("%d", num[3][3]);
    break; 
  case 3:
    num[3][3]={{6, 7, 2}, {1, 5, 9}, {8, 3, 4}};
    printf("%d", num[3][3]);
    break; 
  case 4:
    num[3][3]={{6, 1, 8}, {7, 5, 3}, {2, 9, 4}};
    printf("%d", num[3][3]);
    break;
  case 5:
    num[3][3]={{8, 3, 4}, {1, 5, 9}, {6, 7, 2}};
    printf("%d", num[3][3]);
    break; 
  case 6:
    num[3][3]={{4, 9, 2}, {3, 5, 7}, {8, 1, 6}};
    printf("%d", num[3][3]);
    break; 
  case 7:
    num[3][3]={{2, 7, 6}, {9, 5, 1}, {4, 3, 8}};
    printf("%d", num[3][3]);
    break;
  }
}

i get this when i compile it

 Æ@DDK5LN1X ~
$ gcc 56.c
56.c: In function `main':
56.c:14: error: parse error before '{' token
56.c:18: error: parse error before '{' token
56.c:22: error: parse error before '{' token
56.c:26: error: parse error before '{' token
56.c:30: error: parse error before '{' token
56.c:34: error: parse error before '{' token
56.c:38: error: parse error before '{' token
56.c:42: error: parse error before '{' token

sorry for such a newbie question and program All it is doing is randomly showing the possible answers to a 3x3 magic square according to the random number that is generated and inserted into int a.

[v0id]

You can not give new values to arrays, using the {}-operators. You can only do that, when you're initializing. You've to use the =-operator explicit.

num[3][3] = 8; // Allowed
num[3][3] = {{8, 1, 6}, {3, 5, 7}, {4, 9, 2}}; // Disallowed

[siren]

thank you v0id for helping me everytime!!! It's always very helpful and I learned what I was doing wrong, but it still isn't working. This is what I've changed so far..

#include<stdio.h>
#include <stdlib.h>
#include <time.h>

main()
{   
  int a,i,j;
  int num[2][2];
  srand((unsigned)time(NULL));
  a = rand() % (7 + 1);
 
  switch(a){
  case 0:
    num[0][0]=8;
    num[0][1]=1;
    num[0][2]=6;
    num[1][0]=3;
    num[1][1]=5;
    num[1][2]=7;
    num[2][0]=4;
    num[2][1]=9;
    num[2][2]=2;
    for(i=0;i<2;i++){
      for(j=0;j<2;j++){
	printf("%3d",num[i][j]);}}
    break;
  case 1:
    num[0][0]=4;
    num[0][1]=3;
    num[0][2]=8;
    num[1][0]=9;
    num[1][1]=5;
    num[1][2]=1;
    num[2][0]=2;
    num[2][1]=7;
    num[2][2]=6;
    for(i=0;i<2;i++){
      for(j=0;j<2;j++){
	printf("%3d",num[i][j]);}}
    break;
    
  case 2:
    num[0][0]=2;
    num[0][1]=9;
    num[0][2]=4;
    num[1][0]=7;
    num[1][1]=5;
    num[1][2]=3;
    num[2][0]=6;
    num[2][1]=1;
    num[2][2]=8;
    for(i=0;i<2;i++){
      for(j=0;j<2;j++){
	printf("%3d",num[i][j]);}}
    break;
  case 3:
    num[0][0]=6;
    num[0][1]=7;
    num[0][2]=2;
    num[1][0]=1;
    num[1][1]=5;
    num[1][2]=9;
    num[2][0]=8;
    num[2][1]=3;
    num[2][2]=4;
    for(i=0;i<2;i++){
      for(j=0;j<2;j++){
	printf("%3d",num[i][j]);}}
    break;
  case 4:
    num[0][0]=6;
    num[0][1]=1;
    num[0][2]=8;
    num[1][0]=7;
    num[1][1]=5;
    num[1][2]=3;
    num[2][0]=2;
    num[2][1]=9;
    num[2][2]=4;
    for(i=0;i<2;i++){
      for(j=0;j<2;j++){
	printf("%3d",num[i][j]);}}
    break; 
  case 5:
    num[0][0]=8;
    num[0][1]=3;
    num[0][2]=4;
    num[1][0]=1;
    num[1][1]=5;
    num[1][2]=9;
    num[2][0]=6;
    num[2][1]=7;
    num[2][2]=2;
    for(i=0;i<2;i++){
      for(j=0;j<2;j++){
	printf("%3d",num[i][j]);}}
    break;  
  case 6:
    num[0][0]=4;
    num[0][1]=9;
    num[0][2]=2;
    num[1][0]=3;
    num[1][1]=5;
    num[1][2]=7;
    num[2][0]=8;
    num[2][1]=1;
    num[2][2]=6;
    for(i=0;i<2;i++){
      for(j=0;j<2;j++){
	printf("%3d",num[i][j]);}}
    break;
  case 7:
    num[0][0]=2;
    num[0][1]=7;
    num[0][2]=6;
    num[1][0]=9;
    num[1][1]=5;
    num[1][2]=1;
    num[2][0]=4;
    num[2][1]=3;
    num[2][2]=8;
    for(i=0;i<2;i++){
      for(j=0;j<2;j++){
	printf("%3d",num[i][j]);}}
    break;
  }
}

the program runs fine, but it only outputs one number. I really don't know how I can output the whole matrix...sorry for so many questions

[v0id]

I've responded to your other thread. In the response I provided an example, including how to fill and print matrices.