4 by 4 sudoku without using arrays

[libbylibra]

I'm trying to use loop...
But it seems a bit too complicated...

[BlaineSch]

they are not that bad lol

basically look at this:

while(true) {
//do this
}

basically you see "while" "true" and "do this"

while is the type of loop. 2 main loops are "for" and "while" I like while the most. Basically this while loop will continue as long as the statement in side the () are true so 1==1 is always true and true is always true so it will always be true and basically be and infinite loop

it executes the stuff inside of the {} brackets which is just a comment so it will basically do nothing forever

int i = 0;
while(i <= 10) {
	cout << "hello" << endl;
	i++;
}

This one does the same thing. It starts with "i" equaling 0, and keeps looping, every time increasing the value of i, and once i is not less than or equal to 10 it quits running the code.

Make sense?

Control flow - Wikipedia, the free encyclopedia

[libbylibra]

Yeah.
Thanks blainsch~
Now I'm much more clear with the whole thing.
I need to int all the variables right? (ex: r1c2 for row1column 2)

[mosyemessy]

hey i did it!!! this is only one block of 12. only copy paste and and change the variables. and i could introduce a function.

for (int i=1; i<=4; ++i)
  {
   if (c1r1==i) for (int j=1; j<=4; ++j)
   {
     if (j==i) j++;
     if (j<=4 and c1r2==j) for (int k=1; k<=4; ++k)
      {
        if (k==i or k==j) k++;
        if (k==i or k==j) k++;
        if (k<=4 and c1r3==k) for (int l=1; l<=4; ++l)
         {
           if (l==i or l==j or l==k) l++;
           if (l==i or l==j or l==k) l++;
           if (l==i or l==j or l==k) l++;
           if (l<=4 and c1r4==l) point++;
         }
      }
   }
  }

[mosyemessy]

c1r1 is column 1 row 1.

[Ajiz Zone]

for (int i=1; i<=4; ++i)
{
if (c1r1==i) for (int j=1; j<=4; ++j)
{
if (j==i) j++;
if (j<=4 and c1r2==j) for (int k=1; k<=4; ++k)
{
if (k==i or k==j) k++;
if (k==i or k==j) k++;
if (k<=4 and c1r3==k) for (int l=1; l<=4; ++l)
{
if (l==i or l==j or l==k) l++;
if (l==i or l==j or l==k) l++;
if (l==i or l==j or l==k) l++;
if (l<=4 and c1r4==l) point++;
}
}
}
}

hai.. i'm new to c++ but i quite like the code top there...
can some one help to explain it... when i see that quite confusing..
i hope genius around this site help to explain it.

[WingedPanther]

It attempts to find (part of) a solution to a 4x4 sudoku through brute force. If you trace through the code by hand, you'll quickly see what it's doing.

[kiddies]

ohhh, if w wanna make a sudoku, we have to use a nested loop,

[Mathematix]

Hint: 'structures'

These would allow you to group the data making up the Sudoku array without using arrays.

I'll leave it for you to stew over for a bit.